Question

4 upon 2 + root 3 + root 7 is equals to a root + b root minus root c

Answer 1

$\frac{4}{2 + \sqrt{3} } + \sqrt{7} \\ \\ = ( \frac{4}{2 + \sqrt{3} } ) + \sqrt{7} \\ \\ = \frac{4}{(2 + \sqrt{3} )} \frac{(2 - \sqrt{3} )}{(2 - \sqrt{3}) } + \sqrt{7} \\ \\ = 8 - 4 \sqrt{3} + \sqrt{7} \\ \\ = \sqrt{64} - \sqrt{48} + \sqrt{7}$

hope it helps