Question

4 वर्षों के अंतराल में जन्मे 4 बच्चों की आयु का योग 48 है तो छोटे बच्चे की आयु ज्ञात करो​

Answer 1

Answer:

thanks for free points

Answer 2

Answer:

Explanation:

Let the ages of children be x, (x + 4), (x + 8) and (x + 12) years.

Then, x + (x + 4) + (x + 8) + (x + 12) = 48

4x = 24

x = 6

Age of the youngest child = x = 6 years.