Question

4. What is distance between point (6, 8) and ongin​

Answer 1

Answer:

The distance of the point P(−6,8) from the origin is 62+82 =36+64 =100 =10 units

Answer 2

$\sf Distance \: \: from \: \: Origin \: = \sqrt{ {x}^{2} + {y}^{2} }$

$\sf = \sqrt{ {( 6)}^{2} + {( 8)}^{2} } = \sqrt{36 + 64 } = \sqrt{100} = 10 \: \: units$

• Distance between point (6, 8) and origin is 10 units

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