Question

4) What is the 6th from of the
A.P. 12,9,6​

Answer 1

Answer:

6th term is -3

Step-by-step explanation:

a= 12 (given) first term  

d= 9-12 (Common difference)

  =-3

6th term = a+(n-1)d  

= 12+(6-1)(-3)  

= 12+5(-3)  

= 12+(-15)  

= 12-15  

= -3

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Answer 2

Given Sequence is

12,9,6,,,,,,,,

⇒First term(a) = 12

⇒common difference (d) = 9-12=-3

⇒number of term(n) - 6

Formula

⇒Tₙ = a+(n-1)d

Put the value in formula

⇒T₆ = 12+(6-1)× -3

⇒T₆ = 12 - 5×3

⇒T₆ = 12 - 15

⇒T₆ = -3

Answer

⇒T₆ = -3

                                               

More Information about sequence and series

⇒a,b,c are in AP ; 2b = a+c , GP ; b²=ac and HP ; b = (2ac)/(a+c)

⇒AM = (a+b)/2 , G= √(ab) and H = (2ab)/(a+b)

⇒A≥G≥H        In Equality Based