Math, asked by shreekumari76, 10 months ago

(4.) What is the greatest number of 4-digit which
when divided by any of the numbers 6, 9, 12 and
17 leaves a remainder of 1?
(a) 9997 (b) 9793 (c) 9895 (d) 9487​

Answers

Answered by javidroyal
2

Answer:

12 is the dividend of9997 leaves a reminder of 1

Answered by saurabh2699
0

Answer: (b) 9793

Step-by-step explanation:

L.C.Mof6,9,12,17=612

Largest 4 digit number which is divisible by 612  is 9792

Now adding reminder 1 will get Largest 4 digit number will be 9792+1 = 9793

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