4 whole numbers are each rounded to the nearest 10
the sum of all 4 rounded numbers is 90
what is the maximum possible sum for the original 4 numbers
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Answered by
6
Answer:
those numbers are 50+20+10+10
Step-by-step explanation:
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Answered by
2
Step-by-step explanation:
well, 10 + 20 + 30 = 60
and, 60 + 30 = 90
So, the numbers could be 9 + 19 + 29 + 29 = 86
or, if they must differ from each other, then,
9 + 19 + 29 + 28 = 85
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