4. Without actual calculating the cubes, find the value of each of the following (1) (-10)3 + (7)3 + (3)° - 34207943 Gry (28) + (-15) + (-13) 3 5 (iv) (0.2)2-(0.3)3 + (0.1)3 3 6
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i) (-12)³ + (7)³ + (5)³
Let x = -12, y = 7, z = 5
Then x + y + z = -12 + 7 + 5 = 0
We know the algebraic identity, if x + y + z = 0 then x³ + y³ + z³ = 3xyz
Thus, (-12)³ + (7)³ + (5)³ = 3(-12)(7)(5)
= -1260
ii) (28)³ + (-15)³ + (-13)³
Let x = 28, y = -15, z = -13
Then x + y + z = 28 - 15 - 13 = 0
We know the algebraic identity, if x + y + z = 0 then x³ + y³ + z³ = 3xyz
Thus, (28)³ + (-15)³ + (-13)³ = 3(28)(-15)(-13)
= 16380
HOPE IT HELPS U :D
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