Question

If one of the root of the quadratic equation 3y^2 -ky + 8 = 0 is 2/3 , then find K. Activity : One of the root of the quadratic equation 3y^2 – ky + 8 = 0 is. ………… Substitute y = 2/3 in the equation , 3 ( ……)^2 – k( 2/3) + 8 = 0 So , 4/3 – 2k/3 + 8 = 0 So , 4 – 2k + 24 = 0 So , 2k =……….. , So, K = ………..​

Answer 1

Answer:

k=14

Step-by-step explanation:

3y²-ky+8=0

one root of the quadratic is 2/3

put y=2/3

3(2/3)²-k(2/3)+8 =0

3(4/9)-2k/3+8=0

4/3-2k/3+8=0

(4-2k)/3 = -8

(4-2k) =-8×3

(4-2k) = -24

-2k = -24 -4

-2k = - 28

k = 28 /2

k = 14