4 women & 6 men have to be seated in a row given that no two women can sit together. how many different arrangements are there.
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Let womens be w1 ,w2,w3,w4 and mens be m1, m2 ,m3 ,m4 ,m5 ,m6
therefore it should be
m1m2,m1m3,m1m4,m1m5,m1m6.m2m3m,m2m4,m2m5,m2m6,m3m4,m3m5,m3m6,m4m5,m4m6,m5m6,m1w1,m1w2,m1w3,m1w4,m2w1,m2w2,m2w3,m2w4,m3w1,m3w2,m3w3,m3w4,m4w1,m4w2,m4w3,m4w4
therefore it should be
m1m2,m1m3,m1m4,m1m5,m1m6.m2m3m,m2m4,m2m5,m2m6,m3m4,m3m5,m3m6,m4m5,m4m6,m5m6,m1w1,m1w2,m1w3,m1w4,m2w1,m2w2,m2w3,m2w4,m3w1,m3w2,m3w3,m3w4,m4w1,m4w2,m4w3,m4w4
superrv002:
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