CBSE BOARD XII, asked by Anonymous, 8 months ago

4/x+1 +7/y+2=2, 10/x+1+14/y+2=9/2​

Answers

Answered by Anonymous
23

Answer:

x= 3 & y = 5

Explanation:

let 1/(x+1) = u and 1/(y+2) = v

4u+7v = 2 .......eq1

10u+14v = 9/2

20 u+ 28 v = 9 ......eq2

Multiply eq1 by 5

we get 20 u + 35 v = 10 ......eq3

Subtract eq2 and eq3

20 u+ 28 v - 20 u - 35 v = 9 -10

-7 v = -1

v = 1/7 .....eq4

put value of v into eq1

4u+7(1/7) = 2

4 u +1 = 2

4 u = 2-1

4 u = 1

u = 1/4 .....eq5

Put the value of u and v into 1/(x+1) = u and 1/(y+2) = v

1/(x+1) = u

1/(x+1) = 1/4

On cross multiplying ,we get x+1 = 4

x = 4-1

x = 3

1/(y+2) = v

1/(y+2) = 1/7

y+2 = 7

y = 7-2

y = 5

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