4^{x^2+2}-9{2^(x^2+2)}+8=0
find x
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1
Answer:
Given that 4
x
2
+2
−(9)2
x
2
+2
+8=0
⇒(2
x
2
+2
)
2
−9(2
x
2
+2
)+8=0
On substituting t=2
x
2
+2
in above equation, we get
t
2
−9t+8=0
⇒t=1,8
Therefore, 2
x
2
+2
=1=2
0
⇒x
2
+2=0⇒ no solution
and 2
x
2
+2
=8
⇒x
2
+2=3
⇒x=±1
finitely many points from the set of all intergers
exactly two integers
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