Question

(4-x) ^2-2x factorize using middle term method​

Answer 1

$\huge{\green{\underline{\underline{\bold{Solution:-}}}}}$

$({4 - x})^{2} - 2x \\ 16 + {x}^{2} - 2(4)(x) - 2x \\ 16 + {x}^{2} - 8x - 2x \\ 16 + {x}^{2} - 10x \\ {x}^{2} - 10x + 16 \\ {x}^{2} - 8x - 2x + 16 \\ x(x - 8) - 2(x - 8) \\ (x - 2)(x-8) \\ \red{\Large{\sf{x = 8 \: (or) \: 2}}}$

Hope It Helps You ✌️

Answer 2

Answer:

Hope It Helps You ✌️

Mark me as Brainliest Answer plz.