Question

(4-x)^2-2x

Please solve ​

Answer 1

Question :

To solve the problem $(4-x)^2-2x$

Formula Used :

$(a+b)^2=a^2+b^2+2ab$

Solution :

$(4-x)^2-2x$

Rearrange the terms -  In descending order of power of variable and then constant

$= (-x \:+4)^2-2x\\\\\\\to(a+b)^2=a^2+b^2+2ab\\\\\\=(-x)^2+4^2+(2\times-x\times4)-2x\\\\\\=x^2+16+(-8x)-2x\\\\\\=x^2+16-8x-2x\\\\\\=x^2+16+(-8x-2x)\\\\\\=x^2+16+(-10x)\\\\\\\ =x^2+16-10x\\\\\\=x^2-10x+16$

Answer :

x² -10 + 16 is the answer for the problem

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