Question

Hey ..

$2x {}^{2} - 9x + 10 = 0$
Solve it ...
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Answer 1

$2 {x}^{2} - 9x + 10 = 0$

$2 {x}^{2} - 4x - 5x + 10 = 0$

$2x(x - 2) - 5(x - 2) = 0$

$(2x - 5)(x - 2) = 0$

$\orange{ \therefore x = 2 \: \: or \: \: \frac{5}{2} }$

Answer 2

Answer:

   $2x^{2} - 9x + 10 = 0$

⇒ $2x^{2} -x( 5+4) + 10 = 0$

⇒ $2x^{2} - 5x - 4x + 10 = 0$

⇒ $x( 2x - 5) - 2( 2x-5) = 0$

⇒ $(2x-5)(x-2) = 0$

either,  $2x-5 = 0$            or,   $x-2=0$

          ⇒ $x = \frac{5}{2}$                    ⇒  $x = 2$

∴   x =  5/2  or  2    (ans)

Hope it helps you !!!

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Step-by-step explanation: