4^x+3=112 + 8 * 4^x, find (18x)^3x
Answers
Answer:
4^(x+3) = 112 + 8 x 4^x
Rewriting everything in powers of 2, where possible
2^(2x + 6) = 112 + 2^3 x 2^2x
2^(2x + 6) = 112 + 2^(2x +3)
2^(2x +6) - 2^(2x + 3) = 112
Taking 2^(2x +3) common,
2^(2x +3) [ 2^3 - 1 ] = 112
2^(2x + 3) = 112/7
2^(2x + 3) = 16
Comparing powers, we obtain,
2x + 3 = 4
Hence, x = 1/2
And further, (18x)^3x = (18/2)^3/2 = (9)^3/2 = 27 gives the answer to your question.
Step-by-step explanation:
Answer:
2^(2x + 6) = 112 + 2^3 x 2^2x
2^(2x + 6) = 112 + 2^(2x +3)
2^(2x +6) - 2^(2x + 3) = 112
Taking 2^(2x +3) common,
2^(2x +3) [ 2^3 - 1 ] = 112
2^(2x + 3) = 112/7
2^(2x + 3) = 16
Comparing powers, we obtain,
2x + 3 = 4
Hence, x = 1/2
And further, (18x)^3x = (18/2)^3/2 = (9)^3/2 = 27 gives the answer to your question.
Step-by-step explanation:
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