Question

4/x+3y=14 3/x-4y=23 by elimination method.

give me correct answer.​

Answer 1

Answer:

Taking 1/x = u, the given equation becomes

$\sf \: 4u + 3y = 14 \: \: \: \: \: \: \: \: \: \: …………(i)$

$\sf \: 3 u – 4y = 23…………(ii)$

Adding (i) and (ii), we get

$\sf \: 4u + 3y + 3u – 4y = 14 + 23$

$\sf \: ⇒ 7u – y = 37$

$\sf \: ⇒ y = 7u – 37 \: \: \: \: \: \: \: …………(iii)$

Using (iii) in (i),

$\sf \: 4u + 3(7u – 37) = 14$

$\sf \: ⇒ 4u + 21u – 111 = 14$

$\sf \: ⇒ 25u = 125$

$\sf \: ⇒ u = 5$

$\sf \: ⇒ x = 1/u = \frac{1}{5}$

Putting u= 5 in (iii), we find y

$\sf \: y = 7(5) – 37$

⇒ y = -2 Hence, the solution for the given

system of

equations is x = 1 5and y = -2

Answer 2

Answer:

Equation (1)×3 :

x

12

+9y=42

Equation (2)×4 :

x

12

−16y=92

Subtract two equations ;

⇒25y=−50

⇒y=−2

Substituting 'y' in equation (1),we get ;

⇒x=

5

1

refer upper attelachment