4^x-4^x-1=24 find the value of 2x^x
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Answered by
2
Answer:
4^x-4^x-1=24
4^x-4^x × 4^-1=24
4^x (1-4^-1)=24
4^x (1-1÷4)=24
(taking LCM)
4^x (4-1÷4)=24
4^x (3÷4)=24
4^x=24×4÷3
(on solving 24÷3 =8)
4^x=8×4÷1
4^x=32
(2^2)^x=2^5
2^2x=2^5
Sice the bases are same we equate the powers,therefore
2x=5
x=2.5
Solve further to find the value of 2x^x
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Answered by
1
Answer:
Answer:
4^x-4^x-1=24
4^x-4^x × 4^-1=24
4^x (1-4^-1)=24
4^x (1-1÷4)=24
(taking LCM)
4^x (4-1÷4)=24
4^x (3÷4)=24
4^x=24×4÷3
(on solving 24÷3 =8)
4^x=8×4÷1
4^x=32
(2^2)^x=2^5
2^2x=2^5
Sice the bases are same we equate the powers,therefore
2x=5
x=2.5
Solve further to find the value of 2x^x
@#opeless
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