Math, asked by Panchapakesan9550, 1 year ago

4^x-4^x-1=24 find the value of 2x^x

Answers

Answered by Anonymous
2

Answer:

4^x-4^x-1=24

4^x-4^x × 4^-1=24

4^x (1-4^-1)=24

4^x (1-1÷4)=24

(taking LCM)

4^x (4-1÷4)=24

4^x (3÷4)=24

4^x=24×4÷3

(on solving 24÷3 =8)

4^x=8×4÷1

4^x=32

(2^2)^x=2^5

2^2x=2^5

Sice the bases are same we equate the powers,therefore

2x=5

x=2.5

Solve further to find the value of 2x^x

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Answered by Anonymous
1

Answer:

Answer:

4^x-4^x-1=24

4^x-4^x × 4^-1=24

4^x (1-4^-1)=24

4^x (1-1÷4)=24

(taking LCM)

4^x (4-1÷4)=24

4^x (3÷4)=24

4^x=24×4÷3

(on solving 24÷3 =8)

4^x=8×4÷1

4^x=32

(2^2)^x=2^5

2^2x=2^5

Sice the bases are same we equate the powers,therefore

2x=5

x=2.5

Solve further to find the value of 2x^x

@#opeless

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