Question

4\x+5\y=7. ;
3\x+4\y=5​

Answer 1

Step-by-step explanation:

let 1/x be p and 1/y be q

Now,

4/x+5/y=7

4p+5q=7 --- equation 1

3/x+4/y=5

3p+4q=5 --- equation 2

by substitution method

p=7-5q/4=28-5q

Now put the value of p in equation 2

3(28-5q)/7+4q=5

84-15q/7+4q=5

84-15q+28q/7=5

84+13q=35