Question

4^x × 64 ^2x = 16 ^x+5.
Value of ^x'

Answer 1

Answer:

x = 1

Step-by-step explanation:

${4}^{x} \times {64}^{2x} = {16}^{(x + 5)} \\ \\ {4}^{x}. {4}^{3(2x)} = {4}^{2(x + 5)} \\ \\ {4}^{(x +6x) } = {4}^{(2x + 5)} \\ \\ 7x = 2x + 5 \\ \\ 7x - 2x = 5 \\ \\ 5x = 5 \\ \\ x = 1$