If cos A - sin A = 1 Prove that cos A sin A = 1 or -1
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I think your question is incorrect
cosA-sinA=1
squaring on both sides
cos^2A+sin^2A-2sinAcosA=1......eq1
as we know
sin^2A+cos^2A=1
so
1-2sinAcosA=1
0=2sinAcosA
sinAcosA=0
ok
let sinAcosA=1
then
from eq1
we get sin^2A+cos^2A=3
which is not possible
and if we let sinAcosA=-1
then from eq1
we get
sin^2A+cos^2A= -1
which is not possible
so question should be
if cos A - sin A = 1 Prove that cos A sin A = 0
#lordcarbin
#apnatimeayega.
cosA-sinA=1
squaring on both sides
cos^2A+sin^2A-2sinAcosA=1......eq1
as we know
sin^2A+cos^2A=1
so
1-2sinAcosA=1
0=2sinAcosA
sinAcosA=0
ok
let sinAcosA=1
then
from eq1
we get sin^2A+cos^2A=3
which is not possible
and if we let sinAcosA=-1
then from eq1
we get
sin^2A+cos^2A= -1
which is not possible
so question should be
if cos A - sin A = 1 Prove that cos A sin A = 0
#lordcarbin
#apnatimeayega.
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