Question

4^x=9 (5^x)
solve kindly

Answer 1

$4^{x}=9(5^{x}) \\ =(\frac{4}{5})^{x}=9 \\ \implies xlog(\frac{4}{5})=log (9)$
And hence
$x= \frac{log(\frac{4}{5})}{log(9)}$

Answer 2

Answer:

(2^2)^x=9(5^x)

2^2x=9(5^x)

2^2x=3^2(5^x)

2^2x=(3^2(5^x))^1

2^2x=3^2(5^x)

Step-by-step explanation: