Question

4 x square + 1 upon 16 y square + xy​

Answer 1

or , 4x²+1/16y²+xy=0
take as the 16 LCM
or , 64x²+16xy +y² =0
or, (8x)²+ 2*8xy+y²=0. [ (x+y)² =x²+2xy+y²]
therefore, (8x+y)² =0
since ;x=-y/8
or y=-8x