Math, asked by afroz6763, 1 year ago

4 x square + 9 y square + 16 Z square + 12 x y - 24 yz -16ZX.

Evalute
[(999)^2- 1]

Answers

Answered by ayaankhan01

❇️Hi!❇️

Refer the attachment

Attachments:

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sachinsingh62: hllo

Answered by Anonymous

SOLUTION

$= > {4x}^{2} + {9y}^{2} + {16z}^{2} + 12xy - 24yz - 16zx \\ = > (2 {x}^{2} ) + (3y) {}^{2} + (-4z) + 2 \times 2 \times 3y-2\times 3y× - 4z \times 4x ×-4z \\ \\ = > (2 {x} + 3y - 4z) {}^{2}$

2).

[(999)^2 -1]

=) (999+1)(999-1)

=) 1000× 998

=) 998000

hope it helps ☺️

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4 x square + 9 y square + 16 Z square + 12 x y - 24 yz -16ZX.Evalute [(999)^2- 1]​