4-xP2=6 find x
P=permutation
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(4-x)!/(4-x-2)! = 6
(4-x) × (4-x-1) × (4-x-2)! / (4-x-2)! = 6
(4-x) × (3-x) = 6
12 - 4x-3x +x^2 = 6
x^2 - 7x +6 = 0
x^2 -1x -6x +6 =0
x(x-1) -6(x-1) = 0
(x-6)(x-1) = 0
x= 6 & 1
hope it helped,
plzzz mark as brainliest........
(4-x) × (4-x-1) × (4-x-2)! / (4-x-2)! = 6
(4-x) × (3-x) = 6
12 - 4x-3x +x^2 = 6
x^2 - 7x +6 = 0
x^2 -1x -6x +6 =0
x(x-1) -6(x-1) = 0
(x-6)(x-1) = 0
x= 6 & 1
hope it helped,
plzzz mark as brainliest........
chitrak:
thank u so much
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