Math, asked by sibdhusharavuri7694, 3 months ago

4. ∆ XYZ in which X =90°, and XY= 9cm,XZ= 5 cm

Answers

Answered by deepanahar1979
0

Answer:

what to do in this??

give the proper question

Answered by priyasingla1994
0

Answer:

YZ =\sqrt{106}

Step-by-step explanation:

Acc. to given statement triangle is seems to be right angled triangle

perpendicular = 9 cm

base = 5 cm

Hypotenuse = \sqrt{perpendicular^{2} + base^{2}  }

                     = \sqrt{9^{2} + 5^{2} }

                     =\sqrt{81+25}

                      = \sqrt{106}

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