Math, asked by ranirashi2, 16 days ago

A frog is at the bottom of a well 10 feet deep. He can jumps 3 feet, but every time he jumps 3 feet, he falls back 2 feet. How many jumps will he have to make to get out of the well?​

Answers

Answered by Moksh28332
0

Step-by-step explanation:

Assuming the frog is sticking to the wall; he effectively jumps 1 foot every time he jumps. (+2–1=1). If the well is ten feet deep and we are assuming the frog is jumping from the 10 ft mark, every jump gains him 1 foot up. We can also assume that he doesn’t lose that foot on the final jump. since he will be ‘out’ of the well. So, 9 jumps to free himself. (Do it by landing spots; Jump 1, 9 ft, 2, 8ft, so on….)

Hope it helps :)

Answered by mufiahmotors
0

Answer:

Assuming the frog is sticking to the wall; he effectively jumps 1 foot every time he jumps. (+2–1=1). If the well is ten feet deep and we are assuming the frog is jumping from the 10 ft mark, every jump gains him 1 foot up. We can also assume that he doesn’t lose that foot on the final jump. since he will be ‘out’ of the well. So, 9 jumps to free himself. (Do it by landing spots; Jump 1, 9 ft, 2, 8ft, so on….)

The frog needs to jump 9 times.

Jump up to 2 feet, fall and land at 1 foot.

Jump up to 3 feet, fall and land at 2 feet.

Jump up to 4 feet, fall and land at 3 feet.

Jump up to 5 feet, fall and land at 4 feet.

Jump up to 6 feet, fall and land at 5 feet.

Jump up to 7 feet, fall and land at 6 feet.

Jump up to 8 feet, fall and land at 7 feet.

Jump up to 9 feet, fall and land at 8 feet.

Jump up to 10 feet and out of the well.

Similar questions