Question

4 years ago Sid was 14 years old her brother was thrice her age what will be there total age in n years

Answer 1

Find their age 4 years ago:

Sid = 14 years old

Brother = 14 x 3 = 42 years old

Find their age now:

Sid = 14  + 4 = 18 years old

Brother = 42 + 4 = 46 years old

Find their age in n years:

Sid = 18 + n  years old

Brother = 46 + n years old

Find their total age:

18 + n + 46 + n = 64 + 2n

Answer: Their total age in n years will be 64 + 2n

Answer 2

$\large{\bold{\underline{\red{Solution:}}}}$


⇒ Sid = $\large{\bold{14\:years}}$

⇒ Brother = $\large{\bold{14 \times 3 = 42 \: years}}$

.

.

$\textit{\underline{Their ages:}}$

⇒ Sid = $\large{\bold{14 + 4 = 18 \:years}}$

⇒ Brother = $\large{\bold{42 + 4 = 46\:years}}$

.

.

$\textit{\underline{Their age in n years:}}$

⇒ Sid = $\large{\bold{18 + n\:years}}$

⇒ Brother = $\large{\bold{46 + n\:years}}$

.

.

$\textit{\underline{Now, their total age:}}$

⇒ $\textbf{18 + n + 46 + n = 64 + 2n}$

.

.

$\textbf{Therefore, their total age in}$$\textbf{\underline{n}}$
$\textbf{years will be as 64 + 2n}$