Question

40. Find two parts
41. Find the ratio in which the line segment joining the points (-3, 10) and (6,-8)
is divided by (-1, 6).
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Answer 1

Answer:

The ratio in which line segment (-3 ,10) and (6,-8) by (-1,6) is 2: 7

Step-by-step explanation:

Let (-1,6) divide line segment into ratio m1 : m2

So by section formula,

(-1,6) = (6m1 +(-3m2)/ m1+ m2 , -8m1 + 10m2 / m1 + m2)

so , -1 = 6m1 -3m2 / m1 + m2 and 6 = -8m1 + 10m2/m1+m2

m1 + m2 = 6m1 - 3m2/ -1

= -6 m1 + 3m2. ...(1)

m1 + m2 = -8m1 + 10m2 / 6. ....(2)

By equation (1) and (2)

-6m1 + 3m2 = -8m1 + 10m2 / 6

6(-6 m1 +3m2 ) = -8m1 + 10m2

-36 m1 + 18m2 = -8 m1 + 10m2

18m2 -10m2. = 36m1 - 8m1

28m1 = 8m2

m1/ m2 = 8 / 28

m1 / m2 = 2/ 7

Therefore the ratio of m1: m2 = 2 : 7