Math, asked by neeraj1251, 1 year ago

40 men can complete a piece of work in 40 days. They
started the work together. But at the end of each 10th
day, 5 men left the job. The work would have been
completed in??! ​

Answers

Answered by OnlyStudy21
4

Answer:

Let a man can do 1 unit / day.

Total work = 40 men ×40 days

= 1600 units

40 men can do the work in 10 days

= 400 units

According to question,

{ 5 men left after to days }

35 men can do the work in 10 days

= 350 units

30 men can do the work in 10 days

= 300

25 men can do the work in 10 days

= 250

20 men can do the work in 10 days

=200

men left 20 - 5 = 15 and

work left = 1600-1500 = 100 unit

They will complete in 100/15 = 6 2/3 days

Total days = 50 + 6 2/3 = 56 2/3 days.

Hope it's Help You

Answered by naveenjoshi01974
2

Let a man can do 1 unit/ day.

Total work = 40men×40days

= 1600 units

40 men can do the work in 10 days

= 400 units

According to question,

(5men left after 10 days)

35 men can do the work in 10 days

= 35×10

= 350 units

30 men can do tlhe work in 10 days

=30×10

=300

25 men can do the work in 10 days

=25×10

=250

20 men can do the work in 10 days

=20×10

=200

men left 20−5=15 and

work left = 1600−1500=100 units

they will complete in

=100/15

=20/3 days

Total days = 50+20/3

= 56 2/3 days

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