Question

40 men can do a piece of work in a given time. if only 30 men can be engaged, 6 more days are needed to complete the given work. in how many days can 60 men do the work

Answer 1

Let 40 men complete work in x days.
Total work=40x
For 30 men, 6 more days required. So, total work= 30×(x+6)=30x+180.
Therefore, 40x=30x+180
Implies 10x =180
X=18. Total work=40x=40×18
For 60 men, days= (40×18)÷60
= 12 days.

Answer 2

Answer:

$60\ men$ can do the same work in $12$ days.

Step-by-step explanation:

Given:-

$40$ men can do a piece of work in a given time.

Only 30 men is engaged, 6 more days are needed to complete the given work.

To find:-

The number of days can 60 men do the work.

Step 1 of 1

Let us suppose that 40 men can do a piece of work in x days.

According to the question,

If only 30 men can do the work then 6 more days are needed to complete the given work, i.e.,

The numbers of days in which 30 men can do the same piece of work is,

= $x\times\frac{40}{30}$

Since 6 more days are needed.

So, the equation becomes,

$x\times\frac{40}{30}$ = x + 6

Cross-multiply the equation as follows:

40x = 30(x + 6)

40x = 30x + 180

4x = 3x + 18

4x - 3x = 18

        x = 18

This implies 30 men can do the same piece of work in 18 days.

Now,

$60$ $men$ can do the same work = $18\times\frac{40}{60}$

                                                    = 12 days

Therefore, 60 men can do the same work in 12 days.

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