Question

40% mixture of 0.2 mol of N2 and 0.8 mol of H2 react to give NH3 according to reaction:
N2 + 3H2 ⇌ 2NH3
The moles of NH3 formed at equilibrium will be

1. 0.16
2. 0.2
3. 0.4
4. 0.24

Answer 1

the answer should be 0.4