Question

40% of a pole is painted blue, 26% is painted green and the rest id painted orange. If the pole is 2.6m long, what length of the pole is painted orange? give the correct answer in two decimal places.

Answer 1

Given that:

• 40% of the pole is painted blue.
• 26% of the pole is painted green.
• Portion of the pole left is painted orange.
• The pole is 2.6m long.

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To find:

• Length of the pole painted orange.

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Solution:

Portion of the pole painted blue = 40%

Portion of the pole painted green = 26%

Portion of the pole painted blue and green = (40+26)%

= 66%

Portion of the pole painted orange = (100-66)%

= 34%

Now, we are given that total length of the pole is 2.6m.

So,

Length of the pole painted orange = 34% of 2.6m

= $\sf \dfrac {34}{100} \times 2.6$

= 0.34×2.6

= 0.884m

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Final answer:

$\sf \orange {Length\ of\ the\ pole\ painted\ orange\ is\ 0.884m\ or\ 88.4cm.}$

Answer 2

Question:

40% of a pole is painted blue, 26% is painted green and the rest is painted orange. If the pole is 2.6m long, what length of the pole is painted orange? Give the correct answer in two decimal places.

Given:-

➲ 40% of the pole is painted blue.

➲ 26% is painted green.

➲ Rest is painted green.

➲ The pole is of 2.6m long.

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To Find:-

The length of the pole painted orange.

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Solution:-

Portion of the pole painted blue = 40%

Portion of the pole painted green = 26%

Portion of the pole painted blue and green = (40+26)% = 66%

Portion of the pole painted orange = (100-66)% = 34%

Now, we are given that total length of the pole is 2.6m.

And,

Length of the pole painted orange = 34% of 2.6m

$\red⟹ \red{\underline{\boxed{\bf{\dfrac{34}{100} \times 2.6}}}}$

$\red ⟹ \red {\underline{\boxed{\bf{0.34}}}} \:  \: {{ \red{\sf{x\:}}}} \red {\underline{\boxed{{\bf{0.34}}}}$

$\large\red\mapsto\red{ \boxed{{\bf{ 0.884 m}}}}$

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Required Answer:-

∴ Length of the pole painted orange ⇝ 0.884 m. ✔