Question

40% passengers from a tarin got down at station a 60% of the remainimg passengers got down at statiok b if there were still 540 passengers in the train how many passengers were

Answer 1

Answer:

There were originally 2250 passengers in the train

Step-by-step explanation:

Let "x" be the original number of passengers

We are given that 40% of them got down at Station A.

This means that 60% of them were still in the train

=> No. of passengers in train after Station A = 60% of x

=> No. of passengers in train after Station A = 0.6*x

Now, we are also given that 60% of those that remained got down at Station B.

Clearly, this is equal to:

60% of (0.6*x)

= 0.6 * (0.6*x)

= 0.36*x

Hence, 0.36*x got down at Station B.

Hence, the number of passengers that remained after Station B

= 0.6*x - 0.36*x

= 0.24*x

This number is given as 5400

∴ 0.24*x = 5400

∴ x = 5400/0.24

∴ x = 2250

Original number of passengers in the train = 2250

Verification:

Original passengers = 2250

No. of passengers getting down at Station A = 40% of 2250 = 900

No. of passengers remaining in train after Station A = 2250-900 = 1350

No. of passengers getting down at Station B = 60% of 1350 = 810

No. of passengers remaining in train after Station B = 1350 - 810 = 540

Thus verified