Question

40.
The equation of motion of a projectile are given
by x = 36t metre and 2y = 96 t - 9.8ť metre,
The angle of projection is,
le​

Answer 1

Explanation:

Answer:

angle of projection = 53°

Explanation:

acceleration in x-direction = 0

acceleration in y-direction = 9.8 m/sq-sec downward

x = 36 t

=> initial speed in x-direction = 36 m/s......(1)

=> ux = 36 m/s .....

now,

2y = 96t - 9.8 t^2

=> y = 48t - (1/2) 9.8 t^2

using eqn, s = ut + (1/2) a t^2

initial speed in y-direction = 48 m/s ....(2)

=> uy = 48 m/s .....

now,

tan (theta) = uy / ux = 48/36 = 4/3

=> theta = atan (4/3) = 53°

hence, angle of projection = 53° = asin(4/5)

************

hope, it helps you.