Question

400 litre mixture contain mille and
water ratio 3:2. If 60litre mixture is present replaced with water, what will be the present ratio
of water & milk in the mixture​

Answer 1

$Answer: \frac{51}{49}$

Given

• 400L mixture of water and milk with ratio 3:2
• 60L mixture is replaced by water

To Find

• New ratio of milk and water

Step-by-step explanation:

in 400L:-

• Amount of milk=240L

• Amount of water=160L

Now 60L of mixture is separated

• Left amount of milk=204L
• left amount of water=136L

Now 60L water is added

• new amount of milk=204( no change as water is added
• new amount of water =196L

New ratio

$\frac{204}{196} = \frac{51}{49}$

51:49

Additional information

• method to find of amount from ratio just add the given ration and divide the part by added part than multiply with whole amount
• for example to find amount of x in 60L solution of x and y combining in ration x:y
• $add \: ratios \: = x + y$
• now divide x by x+y. than multiply with 60

$\: amout \: of \: x \: is = \frac{x}{x + y} \times 60$