Question

400 V -
By For equilibrium
262)
3 Fe(s) + 4H2O(g) Fe3O4(s) + 4 H (9)
Pressure exerted by water vapurs was 40% of total
pressure at equilibrium. Find equilibrium constant
(1) 1.5
(2) 2.25
(3) 3.37
(4) 5.06​

Answer 1

Answer:

for 40%of total pressure at equilibrium is 2.25

Answer 2

Answer:(4) 5.06

Explanation:3 Fe(s) + 4H2O(g) gives  Fe3O4(s) + 4 H(g)

at equilibrium

pressure is exerted by water vapour and hydrogen gas

• pressure exert by water vapour= 1-x=0.4 and x=0.6 i.e. pressure=0.4
• pressure exert by hydrogen gas =x=0.6
• Kp=[H2]^4/[H2O]=0.6^4/0.4^4=5.06