Question

A particle is projected with a speed V from a
point O making an angle of 30° with the vertical.
At the same instant, a second particle is thrown
vertically upwards with a speed v from a point
A. The two particle reach H, the highest point
own the parabolic path of particle one
simultaneously. Then ratio V/v is-
(A) 3 root2
(C)2/root3
(B) 2 root3
(D) root3/2​

Answer 1

Answer:

H(max)= V^2(sinø)^2/2g (in projectile)

H(max)= v^2/2g (verticle thrown)

V^2(sinø)^2/2g=v^2/2g

V/v=1/sinø

Wherevø=60° (with horizontal)

V/v=2/root3

Explanation:

Answer 2

Answer:

Refer to the attachment