Question

40°20' change redian​

Answer 1

Answer:

121π÷540 radins this is the answer

Answer 2

40°20' = 40° + 20'

$= {40}^{o} + ( \frac{1}{60} ) {20}^{o} = {40}^{o} + \frac{ {1}^{o} }{ {30} } \\ = \frac{ {1201}^{o} }{30} \\ \\ we \: know \: that \\ {\pi}^{c} = {180}^{o} \\ {1}^{o} = \frac{ {\pi }^{c} }{180} \\ \\ so \\ \frac{ {1201}^{o} }{30} = \frac{1201}{30} \times \frac{ {\pi}^{c} }{180} = \frac{1201 {\pi}^{c} }{5400} \\ \\ hence \\ {40}^{o} {20}^{ - } = \frac{1201 {\pi} }{5400} radians$