Question

(-41)×102 in suitable properties

Answer 1

Heya harsh...

(−41) × 102

= (−41) × (100 + 2)

= (−41) × 100 + (−41) × 2
Using... [a × (b + c) = (a × b) + (a × c)]

= − 4100 − 82 = −4182

Answer 2

Answer:

Hey Harsh,

Your answer is -4182

Step-by-step explanation:

Let me explain you

(−41) × 102

= (−41) × (100 + 2)

= (−41) × 100 + (−41) × 2

Using... [a × (b + c) = (a × b) + (a × c)]

= − 4100 − 82

= - 4182

Thanks