Question

41.
12 men and 16 women together
can complete a work in 4 days. It
takes 80 days for one man alone to
complete the same work, then how
many days would be required for
one women alone to complete the
same work? RRB NTPC (Phase 1) 2016
(1) 160
(2) 150
(3) 130
(4) 175​

Answer 1

Answer:

12 men and 16 women together can complete a work in 4 days.

$\frac{12}{x} + \frac{16}{y} = 1$

It takes 80 days for one man alone to complete the same work,

$\frac{12}{80} + \frac{16}{y} = 1 \\ \frac{16}{y} = 1 - \frac{3}{20} \\ \frac{16}{y} = \frac{17}{20} \\ y = \frac{320}{17} \: days$

320/17 = 18.8235294 days would be required for one women alone to complete the same work.