Math, asked by sahel1234, 9 months ago

41=400[(1+r/100)^2)-1]​

Answers

Answered by adityaranjan605
0

Answer:   41=400[(1+r/100)^2)-1]

41=400[(100+r/100)^2 -1]

41= 400[10000+r^2+ 200r/100 -1]

41= 400[10000+r^2+ 200r-100]

41=4[r^2+200r+9900]

41=4r^2+800r+39600

4r^2+800r+39600-41=0

4r^2+800+39559=0

4r^2+442r+358r+39559=0

2r(2r+221)+179(2r+221)=0

(2r+221)(2r+179)=0

r= -221/2    ,    r= -179/2

Step-by-step explanation:

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