Math, asked by Techsrj, 1 year ago

41.75 was paid as the interest on 835 at 25/4 per annum. If the date of lending was 5 January 2009. find the date up to which the interest was paid

Answers

Answered by M18
57
Here,P = 835, R = 25/4% and I = 41.75
So by formula,
T = I*100\P*R
= 41.75*100/835*25/4
=0.8 years = 9.6 months
So answer is 11 October 2009

M18: may be it happen dear
M18: I try it once again
M18: My answer is correct dear
M18: You should check it again
M18: I have calculated and it's 0.8 yrs = 9.6months
M18: And so it is 11 oct 2009
M18: okkk
Techsrj: yes i know 0.8, is correct.. because it was 4/5
Techsrj: after 4/5 we have to do multiply it with 365, then it will come 292 and then answer is 292 days after 5 January 2009 so answer is 24 oct 2009
M18: okkk
Answered by amitnrw
13

Up to 23th Oct , 2009 interest was paid if Rs 41.75 was paid as the interest on Rs 835 at 25/4% per annum. and date of lending was 5 January 2009

Given:

  • P= Rs 835
  • Interest = 41.75
  • R = 25/4 % per annum
  • Date of Lending 5 Jan 2009

To Find:

  • Date up to which interest was paid

Solution:

SI = P * R * T /100

SI = Simple Interest

Step 1 :

Solve for T by substituting given values

41.75 = 835 x (25/4) x T /100

=> T =4/5  Years

Step 2 :

Find number of days by multiplying with 365 ( as 1 year = 365 days)

365 x 4/5 = 292 Days

Step 3 :

Add 292 Days in 5 Jan 2009

Jan = 27 , Feb = 28 , Mar = 31 , Apr 30,  May 31, Jun 30 , Jul 31 , Aug 31 , Sep 30 , Oct 23

Up to 23th Oct , 2009 interest was paid.

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