Question

41. The sum of two numbers is 161. If one of the numbers
is 30% more than the other, then the numbers are​

Answer 1

Answer:

70, 91

Step-by-step explanation:

If the first number = x

30% ofx = 3/10x

2nd number = x + 3/10x

                     =13/10 x

x + 13/10x = 161

23/10x = 161

10x = 161/23 = 7

x  = 10 x 7 = 7

first number = 70

30% of 70 = 21

second number = 70 + 21 = 91

91 + 70 = 161

(pls mark brainliest)

Answer 2

Answer:

The numbers are 91 and 70

Step-by-step explanation:

Let other no. be x

Then one no. = x+30% of x

                       = x+(30/100)×x

                      = x+(3/10) x

                    = x+(3x/10)

                   = (10x+3x)/10=13x/10

According to the question;

x+(13x/10)= 161

(10x+13x)/10=161

23x/10=161

  23x= 161×10

      x= 1610/23=70

One no. = 13x/10=(13×70)/10

                            = 91

Other no. = 70