42) a bag contains 1100 tickets. tickets are numbered from 1, 2 ... 1100 and one card is drawn randomly what is the probability of having 2 as a digit? (a) 190 (b) 200 (c) 250 (d) 400
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I think there is some problem with the options given correct options are as follows:
A. 291/1100
B. 292/1100
C. 290/1100
D. 301/1100
The correct answer is option C. 290/1100
For every 100 19 digits have 2.
Because we r counting the number of digits having, not the number of 2's in 100(here 22,122 these digits will be counted as 1 not 2)
So the answer is ((10*19)+100)/1100.as 200 to 299 there are 100 digits having 2.
That's why its 10*19+100
Solution 2:
Within 1 to 100 there are 19 numbers containing digit 2.2 first is 20 to 29 there are 10 numbers and 2 12,32,-,- ------92.
and 200 to 299 there are 100 numbers. so 1100 contain 290 numbers containing digit 2.(100---19 so 100 contain 190 ,excluding 200 to 299) 190+100=290.
so, 290/1100 is Answer.
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