Question

42
A man weighing 750 N stands on the floor of a lift. Determine the pressure exerted on the
floor when the lift moves upward with on acceleration of 3.5 m/s2, Use D'Alembert's Principle *


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Answer 1

Answer:

The answer is 42

Explanation:

Answer 2

Given:

weight of man = 750N

Acceleration with which man moving upwards = 3.5m/s²

To Find:

the pressure exerted on the floor =?

Solution:

According to the given information, we can draw the free body diagram of the situation, (as shown in the figure given below)

Now, weight of man = 750N

let mass be m

then mg = 750

and g = 10m/s²

thus m = 75

from the FBD (free body diagram) we infer that,

R = ma + mg

R = 75 (3.5) + 75(10)

R = 1012.5 N

thus, the force exerted on floor = 1012.5N

pressure = force/area (note: area is not given)