42% failed in english 52% failed in arithmetic 17% failed in both subjects. if 69 students passed in both subjects then how many students are there in a school?
Answers
Answered by
0
Answer:
300
Step-by-step explanation:
Let the set of students who failed in english be A
the set of students who failed in arithmetic be B
A union B = 17%
No. of elements only in A = n( A ) - n( A union B )
= 42 - 17
25
No. of elements only in B = n(B) - n (A union B )
= 52 - 17
= 35
Total students who failed = 25 + 35 + 17
= 77 %
students who passed = 23 %
23 % = 69
Therefore,
100 % of students = 69/23 *100
= 3 * 100
= 300
Similar questions