Question

42. If a polynomial, represented by a parabola, intersects the x-axis at -3, 4and y- E axis at -2 then the zeroes are:..​

Answer 1

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The point where the polynomial cuts the x-axis is the zero of the polynomial. Since the given polynomial cuts the x-axis at 3 points, the number of zeroes is 3.

Answer 2

Given : a polynomial, represented by a parabola, intersects the

x-axis at -3, 4

y - axis at - 2

To Find : Zeroes

Solution:

Zeroes of the polynomial are the values for which polynomial have value zero

as polynomial, represented by a parabola, intersects the  x-axis at -3, 4

Hence zeroes are  ( -3 , 4)

Additional Info:

p(x) = k(x - (-3))(x - 4)

p(x) = k(x + 3)(x - 4)

y - axis at - 2   =>

p(0) = - 2

=> -2 = k(0 + 3)(0 - 4)

=> -2 = -12k

=>  k = 1/6

p(x) =  (1/6)(x + 3)(x - 4)

polynomial is (1/6)(x + 3)(x - 4)

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