Question

42. When a cricket ball is thrown vertically upwards, it reaches a maximum height of 5 metres.
(a) What was the initial speed of the ball ?
(b) How much time is taken by the ball to reach the highest point? (8 =10 ms?)​

Answer 1

Answer:

Explanation:

a) velocity= √(2gh) m/s

velocity= √(2 ×10×5) m/s  if g=10m/s²

Velocity= 10m/s

b) here final velocity = 0m/s and initial velocity = 10m/s

v=u-gt  here g is retarding the velocity

0=10- 10 t

t= 1sec