Question

420L of the mixture contains pure milk and water in the ratio of 2:5. Now 80 L of water is added to the mixture. Calculate the ratio of milk and water in the resulting mixture. ​

Answer 1

Answer:

10/19

Step-by-step explanation:

Total Quantity = 420 L

Ratio = 2:5

Let the ratios be 2x and 5x

Now,

2x + 5x = 420 (ATQ)

7x = 420

=) x = 60

Milk quantity = 2×60 = 120L

Water quantity = 5×60 = 300L

Added quantity of water = 80L

Now,

$\frac{120+80\\}{300+80} \\\\= \frac{200}{380}\\\\= \frac{10}{19}$

(Here, 80 is added to the numerator as in the denominator, 80 was added and as the division has to be done on both the numerator and denominator, 80 was added on both sides.)

Hence, the ratio becomes 10/19.

Thank You