Question

43. A can do a work in 25 days and B can do the same work in 20 days. If they work
together for 5 days and then A leaves, in how many days can B finish the remaining
work?
(1) 10
(2) 11
(3) 12
(4) 14​

Answer 1

Answer:

2 (11)

Step-by-step explanation:

A can do a work in 25 day

A can do work in 1 day = 1/25

similarly

B can do a work in 20 days

B can do in 1 day = 1/20

A does work in 5 day = (1/25)*5 i.e. 1/5

B does work in 5 day = (1/20)*5 i.e 1/4

Total work done in one day is (1/5)+(1/4)

9/20

Remaining work = 1-(9/20)

11/20

Total days B will take to finished remaining work is

(11/20)/(1/20)

(11/20)*(20/1)

11 days